How To Not Submit A Form If Validation Is False
Solution 1:
$('#form').submit(function(){
return (validateForm1() &&
validateForm(document.forms['dpart2']) &&
validateForm(document.forms['dpart3']))
});
Basically, you return false in the event handler function.
Solution 2:
If the function returns false, form won't be submitted.
$('#form').submit(function(){
returnvalidateForm1()
&& validateForm(document.forms['dpart2'])
&& validateForm(document.forms['dpart3']);
}
});
Solution 3:
Okay, some of the other solutions will have a lazy fail... you probably want all your validation to run, so that all errors are displayed. The presumption is that your validation methods will return false if they fail.
$("#myform").submit(function() {
var ret = true;
ret = validateForm1() && ret;
ret = validateForm(document.forms['dpart2']) && ret
ret = validateForm(document.forms['dpart3'])) && ret
return ret;
});
This way all your validators will be called, but the Boolean value for any failure, will result in a fail.
Solution 4:
If validateForm(...) and validateForm1() return a boolean (true means that no validation error occurred), then you try to do that :
$('#form').submit(function(){
if (!validateForm1() || !validateForm(document.forms['dpart2']) || !validateForm(document.forms['dpart3'])) {
returnfalse;
}
});
Solution 5:
A thought that comes up automatically: Even if you implemented thorough client side validation be prepared to receive any invalid request data on the server that you can possibly imagine.
Client-side validation never keeps you from server-side validation. It is just a bonus in usability.
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